00:01
So in this problem, you're given the following reactive, which is part of the citric acid cycle.
00:07
And you are shown the following reaction mechanism where water attacks this carbon.
00:16
And you can follow the flow of electrons.
00:19
And you want to figure out what the product would be.
00:24
So remember that your electrons are always going from an area of high to low electron density.
00:32
And so the easiest way to do this is to kind of draw out a skeleton of your product.
00:43
So co2 minus, ch2, co2 minus.
00:53
Okay, so here we have these two electrons from this oxygen are going to be forming a new bond between this oxygen and this carbon.
01:04
So you're going to form a new bond with oh2.
01:14
Now remember, because now oxygen is forming three bonds, it's going to have an overall positive charge.
01:23
And now, remember every time that you form bond, you need to break a bond.
01:29
So while you're forming this new oxygen carbon bond, you're also breaking this carbon -carbon -pie bond.
01:36
And as you're breaking this bond, you're also forming a new bond between this carbon and this hydrogen.
01:48
Between this carbon and this hydrogen.
01:55
And again, as you're forming a bond, you're also breaking this hydrogen -oxygen bond.
02:02
So you have h -2 -0...