00:06
In this problem, problem number 27, we have to point out the splitting pattern of different protons in each of the monotics.
00:22
First one, butane, so it replic and a quartet.
00:32
We have a symmetry here.
00:36
Next, vr, ch2, vr.
00:45
Again, here is a single h.
00:49
Both of them will be appear in the same place.
00:52
One signal h c l c l and h it is identical both are identical so they appear as a single one two so we have a internal planar symmetry so we can expect this to have a doublet here and multiply here and a doublet here the next molecule cl h here h here and cl now here again there is similarly so these will appear as a singlet next t -tone a singlet a triplet a multiplet and a singleet 1, 2, 3, 4 signals next we have cl as a triplet a multiplet and a triplet or this will appear as a quintet a quintet next to iso profiles ch2 in this case we have doubled multiple a doublet a doublet and a triplet next benzeneering vr so a single it here a quartet here and then these two one and two these two will appear as doublet this will be double -ed this will be doublet and this as a triplet next molecule c -x -3 it's parametoxy ptollium o -c -c -3 so here is a singlet another single then here a doublet and double it next is cs3 and cs3.
05:04
You can see the cs3 is a singlet because there's no proton and that's in carbon.
05:09
So single here and this will appear at the same place because it's symmetric...
