00:01
Problem 39 says to predict whether a bond between the indicated atoms and a through f is likely to be ionic, covalent, or polar covalent.
00:11
So remember that in general, ionic bonds are formed between a metal and a non -metal.
00:27
A covalent bond is formed between non -metals with similar electronegativities and a polar covalent bond.
00:54
Is between two non -metals with different electromegativities.
01:11
So what that means then is if you consult the periodic table, remember that toward the left -hand side is where the metals are, and the non -metals are toward the right -hand side.
01:22
Rubidium falls on the very left -hand side of the periodic table, and chlorine is toward the right.
01:29
What that means is this is a metal and a non -metal bound to each other, and therefore is likely an ionic bond.
01:39
Two sulfurs bound to each other is two nonmetals and in fact two of the same non -metal.
01:46
And it's therefore symmetrical and non -polar.
01:50
So this is a standard covalent bond.
01:56
Carbon and fluorine bound to each other...