The pOH of the solution is given as 2.58. The concentration of $\mathrm{OH}^-$ can be calculated using the formula:
\[
[\mathrm{OH}^-] = 10^{-\text{pOH}} = 10^{-2.58}
\]
Calculating this, we find:
\[
[\mathrm{OH}^-] \approx 0.026 \text{ M}
\]
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