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Chapter 16, problem 84, from the textbook chemistry, the central science.
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So the question's asking us to predict whether the solution is either basic, acidic, or neutral.
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So what we're going to do is we're going to take the solution and break it into ions and then determine if each of the ions are either basic or acidic.
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And that will help determine which is the overall, which is the overall condition of the solution.
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So for a, we have al, cl3, and whenever you break it down, you have al3 plus and cl minus.
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We know that cl minus is the conjugate base for a very strong acid of hcl.
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So this is very acidic.
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And al3 plus is also acidic.
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Usually ions that have a plus three charge are acidic.
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So we have two things that are acidic.
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So the overall solution is going to be acidic.
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So b.
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We have n -a -b -r.
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So we have n -a -plus, n -b -r -minus.
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First, we know that n -a -plus is a conjugate acid for n -a -o -h, n -b -r -minus is a conjugate base for hbr.
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Are.
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Both of these are strong.
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One is a strong base and one is a strong acid.
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And so they cancel each other out.
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And so therefore the overall substance is going to be neutral.
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Right.
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Part c, we have n -a -c -l -o.
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Once again, we have that n -a, which is going to be...