00:01
Problem we are given eight pairs of compounds with varying concentrations and occasionally some other information and we're told to determine which compound out of each pair will give a lower ph.
00:12
So starting with our first problem we've got two acids so we know we're gonna have a low ph for both but we've got two different concentrations and two different acids.
00:23
Now hcl is a weaker acid than hbr because br minus is a more stable anion so that means overall we're going to have a stronger acid for our hydrobromic acid.
00:36
But not only is it a stronger acid, but we have a higher concentration of it.
00:40
So we have a higher concentration of a stronger acid.
00:44
This one's going to have a lower ph.
00:47
So the answer to our first one would be the 4 .09 times 10 to the negative second molar hydrobromic acid, stronger acid and higher concentration.
00:56
For problem two, we've got 1 times 10 to the negative fifth molar, acetic acid and 1 times 10 to the negative 5th molar formic acid.
01:04
So we have the same concentration of two different acids.
01:08
So really we just need to figure out which one's a stronger acid.
01:11
And from our k .a value, we can see that formic acid is a stronger acid.
01:15
It has a higher ka value, meaning it's stronger.
01:18
So since we have the same concentration and this is the stronger acid, we know that this is going to give us a lower ph.
01:27
So the answer to our second one is the 1 times 10 to the negative 5th formic acid because of its higher k -a value.
01:34
Now for our third one, we're given 22 millimoles of ch3nh2 and ch3 -2nh2.
01:43
So same thing with our previous example.
01:45
We're looking to see which one is just a stronger acid.
01:49
So for this one, we're given a pkb and a kb.
01:53
So for this problem, the first thing that we have to do is actually get them into the same form.
01:58
So let's get them both in the form of kb.
02:02
So if we do 10 to the negative 3 .36, we get our kb value, and our kb value is going to be 4 .37 times 10 to the negative 4th.
02:15
So now we've got two values we can compare.
02:18
Now we know whichever one is going to be the weaker base is the stronger acid.
02:24
So the one with the lower kb value is going to be the stronger acid.
02:29
So our lower kb value is the one here on the left.
02:34
So our 22 millimolar ch3nh2 is going to give us a lower ph.
02:40
They're the same concentration, but we have a weaker base, meaning we have a stronger acid.
02:47
Lower kb means a greater k -a.
02:51
So in that case, our component on the left is going to give us a lower ph.
02:58
Now for our fourth problem, we've got again two of the same concentrations.
03:02
We've got 158 millimolar nh3 and 158 millimolar acetic acid.
03:08
This is an easy problem.
03:10
We have an acid and we have a base.
03:12
Our acid is going to give us the lower ph.
03:15
Disregarding any of the information we were given, we could have figured that out.
03:19
Now, of course, one we're given a pkb and one we're given a pca.
03:22
So if we weren't told that acetic acid was an acid and we didn't know that nh3 was a base because of that lone pair, we could have figured it out that way.
03:31
Lower pka means a stronger acid...