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Predict/Calculate A magician wishes to create the illusion of a 2.74-m-tall elephant. He plans to do this by forming a virtual imageof a 50.0 -cm-tall model elephant with the help of a spherical mirror.(a) Should the mirror be concave or convex? (b) If the model must beplaced 3.00 $\mathrm{m}$ from the mirror, what radius of curvature is needed?(c) How far from the mirror will the image be formed?

(a) concave(b) 7.34 $\mathrm{m}$(c) 16.4 $\mathrm{m}$

Physics 103

Chapter 26

Geometrical Optics

Wave Optics

Cornell University

Simon Fraser University

Hope College

McMaster University

Lectures

02:51

In physics, wave optics is…

10:02

Interference is a phenomen…

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A concave mirror has a rad…

20:13

A concave spherical mirror…

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Predict/Calculate A convex…

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A magician uses a concave …

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A dentist uses a curved mi…

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. Dental mirror. A dentist…

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(III) A 4.5$\cdot$ -cm-tal…

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A 4.5-cm-tall object is pl…

An object is placed in fro…

03:10

(a) A concave mirror forms…

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A spherical, concave shavi…

03:48

A shopper standing 3.00 $\…

06:57

A 1.80 -m-tall person stan…

04:01

(II) A 4.5 -cm tall object…

01:19

When an object is placed 4…

23:00

A spherical mirror is to b…

03:37

question 32 says a magician wishes to create the illusion of a 2.74 meter tall elephant. He plans to do this by forming a virtual image of a 50 centimeter tall model, often help of a spherical mirror. Should the mere B. Khan Cavor convex. Well, the on leeway to make a magnified image bigger than the actual object is to use a con cave mere. So it has to be con Cave B says if the model must be placed three meters from the mere what radius of curvature is needed. So I know my object. Distance is three meters. I also know my object height is they told us a 50 centimeter high elephant, so 500.5 meters. I know the image height. We want our image to be 2.74 meters, 2.74 meters. Now what we're supposed to do next is find the radius of curvature of the Mir, and then also how far from the near will the image be formed. So we're gonna answer those questions together. Um, since we want the object is 0.5 meters. We know the object height compared to the image height. The opposite of that is equal to the object. Distance. Three meters to the image distance D I. And so what we see here is our image. Distance is 0.5 times the image distance is three times 2.74 on Make that negative. So negative 0.5. Oops, sorry. Three times 2.74 divided by negative 0.5 is negative, 16.44 So our image distance is negative. 16.44 meters on That's behind the mirror. And so now that we know our image, distance and our object distance, we can actually find our focal. So remember, one over the object distance plus one over the image distance is one over the focal length, and so I have 1/3 plus one over negative. 16.44 equals one over f. I want to take three inverse plus 16 whips negative 16.44 in verse and then in Vernal that and I see that the focal length is actually 3.67 meters. Now. Remember, the radius of curvature is only half of the focal length, and so I have to are the focal length is half threes of curvature. So I have to multiply that focal length by two to get threes of curvature of the mirror, and I see that our is actually 7.34 meters.

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