00:01
In the first part of this problem, we are asked to calculate the magnitude of charge on each plate.
00:06
We call this charge as q.
00:10
So we can write the charge and the plates of the capacitor as q equals to c, v.
00:17
We call it equation number 1, where the c is the capacitance of the capacitor and v is the voltage between the plates.
00:24
Now we can write the formula for the capacitance of parallel plate capacitor as c equals to kappa, epsilon not a divided by d.
00:37
Here, this kappa is the dialectic constant.
00:40
Absalom not is the permissity of free space.
00:42
A is the area of the plates and d is the separation between the plates.
00:46
Now, setting this value into the above equation, we can write it as 2 equals to kappa, epsilon not a, v, divided by d.
01:02
We call it equation number 2.
01:06
Now, by inserting the values into this equation, we can write it as q equals 2.
01:14
We have the value for kappa as 1 .0 into we have the value for epsilon not as 8 .85...