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Predict/Calculate Microscope objective $A$ is labeled $15 \times$ andobjective $B$ is labeled $25 \times$ (a) Which objective has the longer focallength? Explain. If the image formed by the objective is designedto be 16.3 $\mathrm{cm}$ from the lens, calculate the focal length of the(b) $15 \times$ and (c) $25 \times$ objectives.

a) objective Ab) $1.1 \mathrm{cm}$0.65 $\mathrm{cm}$

Physics 103

Chapter 27

Optical lnstruments

Wave Optics

Rutgers, The State University of New Jersey

Simon Fraser University

Hope College

University of Sheffield

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So in this problem we have two microscopes, uh, objectives. And the first objective has a magnification. Let's go and a off 15 times. And the second objective has a magnification. Let's go and be of 25 times. Both of the objectives are beauts to work at a distance that's called D I off 16.3 ST Emitters. Okay, so there first I think of the problem, we need to explain which of the objectives has the greater focal length. Well, to answer this, we just need to remember that the magnification of the objective is inversely proportional. So the focal lens off the objective. So if we have a shorter for Holland's going to have are greater magnification and vice versa. So the answer to this one has to be m a actually, that sports objective, eh? Objective A. Because objective, eh is the shorter for the shorter magnification. So there needs to be the greater focal length. Well, now the second item, we actually have to calculate that the focal objective length left. So let's see to the 1st 1 that's call this one deep. Hey, it's just going to me f A course to minors 16.3 divided by minus 15. So this is equals to 1.1. Think Team enters and the focal lens off the B 2nd 1 It's Toby Miners 16.3, divided by minus 25. So this is zero point 60 65. Same team enters as we can see. The objective, eh? Has the greater for Colin, and that's the final answer.

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