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Predict/Calculate REfERING TO EXAMPLE $27-6$ Suppose a person'snear-point distance is 67.0 $\mathrm{cm} .$ (a) Is the refractive power of theeyeglasses that allow this person to focus on an object just 25.0 $\mathrm{cm}$from the eye greater than or less than 2.53 diopters, which is therefractive power when the near-point distance is 57.0 $\mathrm{cm} ?$ Theglasses are worn 2.00 $\mathrm{cm}$ in front of the eyes. (b) Find the requiredrefractive power for this person's eyeglasses.

a) greater than 2.53 dioptersb) 2.81 diopters

Physics 103

Chapter 27

Optical lnstruments

Wave Optics

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so similar to the problem. 106 We have a person wearing glasses at a distance off, too. 70 meters from hair eyes and we have, ah, the distance of the object this person can see off 25 centimeters from hair ice. We have to suppose that the near point distance near point distance is going to be 67 70 meters and again referring to the problem 27. For example 27.6. We need to explain if the refractive power off the eyeglass they're allowed this person to focus this object is going to be greater than or less than two points. 53 Diop doctors. Okay, so again, look into the problem. 27 6 Since we know that because the near point is farther than off the example the refractive our off, this lance's should be greater then two points 50 tree Diop tres Because we need to look, the objects are a long distance. So if the distance is farther, the reflective power also going to need to be greater and we can't win now In the second item, we need actually to calculate this value. So how are we going to calculate the refractive power. We know that the refractive hour is just one divided by F. But using the finger ends equation, we know that one divided by F. It's just one divided by the eye, one divided by zero. So we just need to calculate the distance of the image and the distance off the object. But remember, this is the Finland's equation, so these distance is related to glasses and not to the ice. So the distance off the object that we have in here off 25 sentiment er's we need actually to subtract off the distance off the glasses and the same to the near distance, because in your distance is just the distance of the image, plus the distance of the glass to the ice. So the distance of the image we can calculate from here. So let's move on. We know. Then that's the distance of the image is going to be minus 67 miners, too, which gives us miners 65. Same team enters so we can calculate this. Now we're going to get that The reflective power is equal two, one divided by minors. You know 10.65 waas one divided by zero point 23 which is the distance of the object. When we subtract the two centimeters, that gives us a total off two points, 81 day after's. And that's the precise, exactly value off the reflective power of these glasses. And as you can see, it is actually greater, then 2.53 doctors, and that's your final answer.

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