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Predict/Calculate You have two lenses, with focal lengths$f_{1}=+2.60 \mathrm{cm}$ and $f_{2}=+20.4 \mathrm{cm} .$ (a) How would you arrangethese lenses to form a magnified image of the Moon? (b) What isthe maximum angular magnification these lenses could produce? (c) How would you arrange the same two lenses to form a magnified image of an insect? (d) If you use the magnifier of part (c) to view an insect, what is the angular magnification when the insectis held 2.90 $\mathrm{cm}$ from the objective lens?

a) $f_{b}=f_{2} \quad i f_{e} y=f_{1}$b) $=7.85$c) $f o b=f_{1} ; f_{-y}=f_{2}$d)$=-12$

Physics 103

Chapter 27

Optical lnstruments

Wave Optics

Simon Fraser University

University of Winnipeg

McMaster University

Lectures

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Okay, so in this problem, we have two lenses. The first lens has a focal length off to a point six. Same team enters, and the 2nd 1 has a focal lens off 20.4. Same team enters. And in their first itin of this problem, we have to predict how you we would arrange this lens to have a magnify image of the moon. Okay, so remember that this is the first item I think a Remember that to get her magnify image, we have the folk Oh, objective. Divided by the focal. I piss and always remember that the focal objective needs to be bigger. Then the focal eyepiece. That's how we built a telescope. So since we have in this problem that I have to is greater than F one, we can say for sure that the telescope has objective equals the F two, and we have the focal I p's You closed the F one and that's the answer off the first item. The second item. We have to calculate the magnification. Okay, so we already know how to calculate. It's just dividing objective by eyepiece. So we're gonna get here 20 point four divided by 2.6. This is going to be equal to seven point 85. And that's the magnification off this telescope. The turn itin his detergent itin. In this item, we have to rearrange the lens to Butte a microscope. And in the microscope, we have the inverse of the telescope we have that the objective needs to be smaller, then the eyepiece. So here we have objective equals F one and the piece it close F too. You just need to remember that the microscope works the opposite way off the telescope. Okay. Ah, Now we have to calculate the distance off the image off this off this microscope. So what's pushing here? The distance off the image we know using the feelings of creation. The distance of the images. Just one divided by the objective miners one divided by zero, all to the power off minus one. So we're gonna get the I equals one divided by 2.6 miners. One divided by two points. Nine oh, to the power off miners. One, This is equals two 25 saying team enters and now we can calculate the Soto magnification. Actually, the last thing we need to calculate the magnification. So let's circulate in here. It's Toto magnification defined by miners. Do I times and divided by the focal objective and the focal I piss. So this is just miners 25 times 25 divided by 2.6 times 20.4. So this is minus 12. Same team enters. I think you manage 12. This is the magnification. We don't have unities. So the magnification is just miners 12 and that's the final answer.

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