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Pressure cookers increase cooking speed by raising the boiling temperature of water above its value at atmospheric pressure. (a) What pressure is necessary to raise the boiling point to 120.0ºC ? (b) What gauge pressure does this correspond to?

(a) $1.99 \times 10^{5} \mathrm{N} / \mathrm{m}^{2}$(b) $\Delta P=0.98 \times 10^{5} \mathrm{N} / \mathrm{m}^{2}$

Physics 101 Mechanics

Chapter 13

Temperature, Kinetic Theory, and the Gas Laws

Temperature and Heat

Rutgers, The State University of New Jersey

University of Michigan - Ann Arbor

University of Sheffield

McMaster University

Lectures

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Now, if the boiling point is 1 20 degree Celsius, the corresponding pressure required you can look up from the table is 1.99 times in about five. Ask us so that corresponds to apart. You'd appreciate off 1.99 I'm still part five subtracted with the standard pressure ridges 1.1 into 10 Part five Paschal's so that 0.98 to 10 Part five Paschal's What's that?

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