00:01
Hello students in this question we have given the pressure of 1 gram of ideal gas a that is w a equals to 1 gram is found to be 2 bar okay and when 2 gram of another ideal gas that is w b it is equals to 2 gram is introduced then this pressure become p dash equals to 3 bar so we have to determine the relationship between their molecular masses that is m b and m a these are the molecular masses we have to determine the mind the relationship between them.
00:33
So we can write here that the as the temperature is constant, so we can write that p modiplier by volume v, this is equals to p dash multiply by volume v.
00:47
So here we can write that p and volume v, this will be equals to the volume v.
00:54
This can be written as from the ideal gas equation.
00:58
So we can take the complete equation.
01:00
So p v which is equal to n rt, so n can be written as mass of the a gas divided by molecular mass of the a gas multiplied by rt and this pressure will be taken as p.
01:13
And the flask is same, so volume will be remained constant.
01:17
Okay, and for the second situation where p dash pressure is having, so p dash multiplied by v, this will be equals to the total number of moles will be taken here.
01:26
So we can write that w .a divided by m .a...