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Averell H.
Carnegie Mellon University

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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66 Problem 67 Problem 68 Problem 69 Problem 70 Problem 71 Problem 72 Problem 73 Problem 74 Problem 75 Problem 76 Problem 77 Problem 78 Problem 79 Problem 80 Problem 81 Problem 82 Problem 83 Problem 84 Problem 85 Problem 86

Problem 70 Hard Difficulty

Prevention of hip fractures. Falls resulting in hip fractures are a major cause of injury and even death to the elderly. Typically, the hip's speed at impact is about 2.0 $\mathrm{m} / \mathrm{s}$ . If this can be reduced to 1.3 $\mathrm{m} / \mathrm{s}$ or less, the hip will usually not fracture. One way to do this is by wearing elastic hip pads. (a) If a typical pad is 5.0 $\mathrm{cm}$ thick and compresses by 2.0 $\mathrm{cm}$ during the impact of a fall, what acceleration (in $\mathrm{m} / \mathrm{s}^{2}$ and in $g^{\prime}$ s) does the hip undergo to reduce its speed to 1.3 $\mathrm{m} / \mathrm{s} ?$ (b) The acceleration you found in part (a) may seem like a rather large acceleration, but to fully assess its effects on the hip, calculate how long it lasts.

Answer

a) $a=-58 m \cdot s^{-2}, a_{g}=-5.9 g m \cdot s^{-2}$
b) $t=12 \times 10^{-3} \mathrm{s}=12 \mathrm{ms}$

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Video Transcript

So here B Y initial equals two meters per second. So this is Ahh how fast you come down on your hip. Ve y final equals 1.3 meters per second because if you can reduce this velocity to 1.3 meters per second ah, you can reduce damage to the hip. And there's padding on your hip that compresses by two centimeters so we can save point zero to meters. So party is asking us for the velocity felt by your hip so you can save you. I final squared equals B. Why initial squared plus two times, eh? Some. Why Delta y So a supply would equal v y final squared minus v y initial squared divided by two times delta. Why, this is equaling 1.3 squared, minus two squared, divided by two times 20.2 and a subway. I would be equal to negative 57.75 meters per second squared. If you were to divide this by 9.8, you would get a negative 5.89 geeks. No, excuse me. So this does seem like a very high acceleration sixties would make it would cause a great deal of force Teo be placed on the hip. However, the important time is the time this this is being placed on your hip so we can say that v y final It's v y final equals V Y initial plus a tea. And so we can say that Ah b Y final is going to be equal Teo zero because we're coming to arrest you or rather, ve Y final is going to be 1.3 meters per second. This is still in the cushioning. My my apologies. So t would be v y final minus v y initial divided by eh And this would be to 1.3 minus two divided by negative 57.75 and this would equal 0.121 2nd So you're the the hip is on ly being subject to this acceleration for 0.121 seconds. This is approximately equal to 12 milliseconds. So it is extremely short amount of time even though it is ah, large acceleration. This would be your answer for part A. That is the end of the solution. Thank you for watching

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Hugh D. Young

College Physics

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