Question
Product 3 numbers in GP is 216 and the sum of their squares is $189 .$ Then, one of the numbers of this set of numbers is(a) 16(b) 12(c) 20(d) 27
Step 1
Since the product of the three numbers is 216, we have \[(a/r) \cdot a \cdot ar = 216\] Solving this equation gives $a^3 = 216$, so $a = 6$. Show more…
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