00:01
So in this problem, we're dealing with a scenario with championship series and sports games.
00:06
And basically the premise is that two teams are assuming they're evenly matched, will play until one team wins four games.
00:13
So there will be a maximum of four games in the series, or a minimum of four games in the series, and a maximum of seven.
00:20
And in this problem, we're being asked to calculate the different number of ways that the teams can end a championship series in different numbers of games.
00:29
So in part a, we're being asked, how many different sequences of game winners are there in which a series ends in four games? and if a series ends in four games, that means one team wins all of the games.
00:44
And since there are only two teams, there are two ways because either one team wins all of the games or another team wins all of the games.
00:53
In part b, we are doing this calculation but for a five game series.
00:58
And if five games are played, that means one team loses one of the first four games and wins the other games, and wins the other three games, as well as the last game.
01:11
And so in this case, we're going to do a permutation, and the order of the games is important, so that is why we're doing a permutation.
01:20
And basically, we want to figure out how many ways there are for one team to lose one game in the first four games.
01:27
So to do this, we are choosing from the first four games, or we are doing a permutation, and they are losing one game.
01:37
So it's going to be four factorial over four minus one factorial, which is four factorial over three factorial, which is simply four.
01:51
And since there are two teams that could be the winning team, we need to multiply this number by two.
01:58
So 2 times 4 is equal to 8, and that means there are 8 different ways in which these 5 games could be played...