Question
Proof Prove that, if $P(n)$ and $Q(n)$ are polynomials of degree $j$ and $k,$ respectively, then the series$\sum_{n=1}^{\infty} \frac{P(n)}{Q(n)}$converges if $j<k-1$ and diverges if $j \geq k-1$
Step 1
We will apply the comparison test to determine the convergence or divergence of the series $\sum_{n=1}^{\infty} \frac{P(n)}{Q(n)}$. Show more…
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$$\begin{array}{l}{\text { Proof Prove that the power series }} \\ {\sum_{n=0}^{\infty} \frac{(n+p) !}{n !(n+q) !} x^{n}} \\ {\text { has a radius of convergence of } R=\infty \text { when } p \text { and } q \text { are }} \\ {\text { positive integers. }}\end{array}$$
Infinite Series
Power Series
Prove that the power series $$\sum_{n=0}^{\infty} \frac{(n+p) !}{n !(n+q) !} x^{n}$$ has a radius of convergence of $R=\infty$ if $p$ and $q$ are positive integers.
Show that if $p$ and $q$ are positive integers, then the power series $$ \sum_{k=0}^{\infty} \frac{(k+p) !}{k !(k+q) !} x^{k} $$ has a radius of convergence of $+\infty$.
Maclaurin And Taylor Series; Power Series
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