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Today we have combustion of propane and a few questions the answer about that.
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Some stoic amputery questions, different kind of like levels or layers to it.
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Let's get going.
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So a is we're trying to figure out how many moles of water we can get from moles of propane.
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So here's our water and our propane.
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We're going to need those two values.
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So we can see the ratio is four to one, four to one.
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So the setup would be what we want as a conversion factor.
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We want our answer to be in moles of water.
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So i'm putting our standard four moles from the equation to one mole of propane, which is c3h8.
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Sorry, a little tight there.
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But key thing is that unit, moles, and that label, propane is gone.
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We have five times four divided by one.
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We have our 20 moles of water.
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So again, a 4 to 1 ratio kind of makes sense to kind of see that a little bit.
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All right.
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So next, i'm going to do a little erasing.
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Maybe you get that a little smaller.
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And our next little bit is for b.
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We want to figure out now grams, grams to grams, grams of oxygen.
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How many grams of co2? we can get from 18 .5 grams of oxygen.
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So this is how i approach these problems.
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I like one conversion.
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I do and figure out total mass.
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So what that means is i am going to first focus on the two players here, which would be oxygen and co2.
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So i want to interpret the 502.
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That's five moles of oxygen.
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I'm going to basically determine the total mass of five moles of oxygen.
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All right.
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So that is going to be five times 32.
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That's going to be 160 .0 .0 .0...