00:03
The first compound has a molecular formula c4h7 clo, ir absorption 1715.
00:27
It's a teta group.
00:32
Nmr 1 .62 at doublet with a relative area of 3.
00:59
You can say it is cx3.
01:10
Then we have a 2 .33 as synclet again appears to be a c.
01:23
Ch3 glue 4 .32 a quartet appearing as a ch single proton.
01:43
So that comes to 7 in number.
01:49
So the ch3 of the first one should be a cs3 attached to a ch and this should be a simple cs3 attached to no other proton wearing carbon.
02:08
This should be the earlier c .h3 ch.
02:15
So this photo and here is this problem.
02:19
So the structure of the compound, since this is 4 .2 and there is a chlorine multitude where it clearly indicates this carbon is attached with a chlorine molecule.
02:38
So the structure, c .h3, c .h .c .l...