00:01
Problem number six, okay, we are asked to propose structures that satisfy these requirements, okay? so let's go for it for part a.
00:15
Part a, we are given this molecular formula, c2h4o, right? and they want it to have an aldehyde function group, okay? so i want to draw that starting with the aldehyde.
00:35
So an aldehyde would be a carbon with a double bond with oxygen, right? so there's our carbon, double bond with oxygen, and it has a hydrogen.
00:51
Okay.
00:52
And an aldehyde is always terminal.
00:54
So i'm putting it at the end here.
00:57
And we have two carbons.
01:02
And we already have one with our aldehyde, so we only need one more, okay? and then we have four hydrogens.
01:12
Let me highlight that.
01:14
We got four hydrogens, and we have one from aldehyde, so we're going to need three more, which is great, because this carbon could handle three more hydrogens, okay? so that should be our structure for part a.
01:29
Okay, part b.
01:30
We need this molecule to contain carboxylic acid okay so i want to start with drawing the carboxylic acid so we have an oh h group right we got a carbon double bonded to o and there you go actually let me erase this part okay so that's that's your carboxylic acid right and how many carbons do we need we need three okay so i'll go ahead and put two more carbons we need three total right and then we have six hydrogens about six hydrogens okay we already have one here so we need to just add two more okay so i'm gonna add that to our carbons so let me put more space.
02:33
So this second carbon could handle two more hydrogens and this last carbon could handle three more to make it four bonds.
02:41
Okay.
02:43
So that gives us a total of six hydrogens and of course those those two oxygens are in our carboxylic acid.
02:53
Okay.
02:55
So moving on to part c...