00:01
In this question, we're not estimated the energy needed to confine our proton in the nucleus based on the uncertainty principle.
00:12
So the uncertainty principle tells us that delta x times delta p, uncertainty in the momentum and the uncertainty in the position must be always greater than all equals to, which power 2.
00:26
Now we are given the uncertainty of the position.
00:32
Position to be approximately the size of our atomic nuclei, then we can find delta p to be about h bar 2 divided by 5 times 10 power of 15 minus 15.
00:54
So this will give us about 1 .1 times 10 power of minus 20 terms of the si units.
01:04
And we're going to take this to be the kinetic, sorry, the momentum of our proton.
01:17
We are given that we take this uncertainty as the momentum, and we use this to find what is the kinetic energy of the proton.
01:30
So kinetic energy, be just taking the total energy, minus away the rest energy.
01:39
Now in the relativistic case, the total energy given here is equals to p square c square minus m square c4...