00:01
To prove this using induction, we first have to look at the base case at n equals 1.
00:06
So we have on our left -hand side, our first term is 2, and that's going to be equal to n, which is 1, times 3n, so 3 times 1, plus 1, all divided by 2.
00:24
So we solve this, it's pretty easy.
00:28
We have the coefficient of 1, and then we have 3 plus 1 is 4 divided by 2, so we're left with 2.
00:35
And we can see pretty easily that the base case works for this induction point.
00:44
Now we have to look at the inductive case.
00:47
So given the n is equal to k, we know that 2 plus 5 plus 8 plus a whole bunch of other numbers with the same pattern is going to be equal to 3n minus 1.
01:10
And n in this case is going to be k.
01:15
And that's equal to n or k times 3k, minus 1 divided by 2.
01:28
So we go about solving this by adding on the next term.
01:39
So mathematically, this is shown by adding on, which is represented in red, 3 times k plus 1 minus 1 term to the end of our left hand side, our sum of all these terms.
02:02
Now notice this is just the equivalent for our induction step with n equal to k plus 1, k plus 1 instead of n is equal to k.
02:19
So we continue that's equal to 3 times 3k plus 1, all divided by 2.
02:35
And then we have a plus 3 times 3k plus 1.
02:49
And that second 3 is a mistake.
02:52
That shouldn't be there.
02:53
So now we keep going...