Question
Prove that an $n \times n$ matrix with complex entries is unitary if and only if the columns of $A$ form an orthonormal set in $C^{n}$.
Step 1
The conjugate transpose of $A$ is denoted by $A^*$ and is defined by $A^* = \overline{A^T}$, where $\overline{A^T}$ is the conjugate of the transpose of $A$. Show more…
Show all steps
Your feedback will help us improve your experience
Nick Johnson and 51 other Calculus 3 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Prove that if $A$ is any $m \times n$ matrix, then $A^{T} A$ has an orthonormal set of $n$ eigenvectors.
Diagonalization and Quadratic Forms
Orthogonal Diagonalization
Let $U$ be an $n \times n$ orthogonal matrix. Show that the rows of $U$ form an orthonormal basis of $\mathbb{R}^{n}$ .
Orthogonality and Least Square
Orthogonal Sets
Show that if $A$ is an $n \times n$ matrix with complex entries, and if $\mathbf{u}$ and $\mathbf{v}$ are vectors in $C^{n}$ that are expressed in column form, then $$ A \mathbf{u} \cdot \mathbf{v}=\mathbf{u} \cdot A^{*} \mathbf{v} \quad \text { and } \quad \mathbf{u} \cdot A \mathbf{v}=A^{*} \mathbf{u} \cdot \mathbf{v} $$
Hermitian, Unitary, and Normal Matrices
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD