00:01
Okay, so here, part a, we're going to suppose that a and u are both a unitary matrix.
00:07
So then since a and u are unitary, therefore we have that u times u to the h is equal to u to the h times u is equal to the identity, and also a times a to the h is equal to a to the h times a, which is equal to the identity.
00:27
So the matrix t will be unitary if we have t times t to the h is equal to t to the h times t, which is equal to the identity.
00:40
So we consider t times t to the h, and then we have t times t to the h is equal to, well, u -inverse times au, times au all to the h, which is going to give us that t times t to the h is going to to be equal to u inverse times a times a to the h times u inverse to the h which is equal to the identity and then similarly we saw the right hand side and again we get that t to the h um times t is going to be equal to while u inverse times a u all to the h times u inverse times a u and um since u to the h is equal to u inverse we get t to the h times t is going to be equal to u to the h times u which is equal to the identity and therefore we have that t which is equal to u inverse times a u is going to be a unitary a unitary matrix um and then for part b we want to show that the upper triangular matrix, t is diagonal.
02:05
If you know, the columns of a unitary matrices are always going to be orthogonal.
02:11
So here we let part b now, we let t be equal to the determinant of a sub i, j...