Prove that, for the GI/G/c and GI/G/c/K/K steady state queueing systems,
$$
E[q \mid q>0]=\frac{W_q}{P[q>0]},
$$
where $P[q>0]$ is the probability that an arriving customer must queue for service. Note that an arriving customer must queue for service if and only if she finds all the servers busy, but this probability is not necessarily the same as the probability that all the servers are busy; that is, the probability that a random observer finds all the servers busy. Wolff [66] has shown the two probabilities are the same only when the arrival process is Poisson. We have seen that these probabilities are different for the machine repair systems $\mathrm{M} / \mathrm{M} / 1 / \mathrm{K} / \mathrm{K}$ and $\mathrm{M} / \mathrm{M} / \mathrm{c} / \mathrm{K} / \mathrm{K}$.