Question

Prove that, for the GI/G/c and GI/G/c/K/K steady state queueing systems, $$ E[q \mid q>0]=\frac{W_q}{P[q>0]}, $$ where $P[q>0]$ is the probability that an arriving customer must queue for service. Note that an arriving customer must queue for service if and only if she finds all the servers busy, but this probability is not necessarily the same as the probability that all the servers are busy; that is, the probability that a random observer finds all the servers busy. Wolff [66] has shown the two probabilities are the same only when the arrival process is Poisson. We have seen that these probabilities are different for the machine repair systems $\mathrm{M} / \mathrm{M} / 1 / \mathrm{K} / \mathrm{K}$ and $\mathrm{M} / \mathrm{M} / \mathrm{c} / \mathrm{K} / \mathrm{K}$.

   Prove that, for the GI/G/c and GI/G/c/K/K steady state queueing systems,
$$
E[q \mid q>0]=\frac{W_q}{P[q>0]},
$$
where $P[q>0]$ is the probability that an arriving customer must queue for service. Note that an arriving customer must queue for service if and only if she finds all the servers busy, but this probability is not necessarily the same as the probability that all the servers are busy; that is, the probability that a random observer finds all the servers busy. Wolff [66] has shown the two probabilities are the same only when the arrival process is Poisson. We have seen that these probabilities are different for the machine repair systems $\mathrm{M} / \mathrm{M} / 1 / \mathrm{K} / \mathrm{K}$ and $\mathrm{M} / \mathrm{M} / \mathrm{c} / \mathrm{K} / \mathrm{K}$.
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Probability, Statistics, and Queuing Theory with Computer Science Applications, Second Edition (Computer Science and Scientific Computing)
Probability, Statistics, and Queuing Theory with Computer Science Applications, Second Edition (Computer Science and Scientific Computing)
Arnold O. Allen 2nd Edition
Chapter 5, Problem 51 ↓

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- \( E[q \mid q>0] \) is the expected number of customers in the queue given that there is at least one customer in the queue. - \( W_q \) is the average waiting time in the queue for customers. - \( P[q>0] \) is the probability that an arriving customer finds the  Show more…

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Prove that, for the GI/G/c and GI/G/c/K/K steady state queueing systems, $$ E[q \mid q>0]=\frac{W_q}{P[q>0]}, $$ where $P[q>0]$ is the probability that an arriving customer must queue for service. Note that an arriving customer must queue for service if and only if she finds all the servers busy, but this probability is not necessarily the same as the probability that all the servers are busy; that is, the probability that a random observer finds all the servers busy. Wolff [66] has shown the two probabilities are the same only when the arrival process is Poisson. We have seen that these probabilities are different for the machine repair systems $\mathrm{M} / \mathrm{M} / 1 / \mathrm{K} / \mathrm{K}$ and $\mathrm{M} / \mathrm{M} / \mathrm{c} / \mathrm{K} / \mathrm{K}$.
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Key Concepts

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Steady-State Analysis
Steady-state analysis in queueing theory involves studying the long-run behavior of a queueing system when its statistical properties no longer change with time. This framework assumes that the arrival, service, and departure processes have reached equilibrium, thereby enabling the evaluation of performance measures like average waiting times, queue lengths, and server utilization based on constant probabilities and expectations.
Conditional Expectation in Queueing Systems
Conditional expectation is a statistical concept used in queueing models to compute the expected value of a random variable given that a specified event occurs. In this context, finding E[q | q > 0] involves determining the average number of customers in the queue specifically when the queue is non-empty, which provides insight into customer experience during congested periods.
GI/G/c and GI/G/c/K/K Queueing Systems
GI/G/c and GI/G/c/K/K denote classes of queueing systems where the arrival process (denoted by GI) is generally distributed and independent, the service times (the first G) are also generally distributed, and 'c' represents the number of servers. The additional K in the GI/G/c/K/K system indicates a finite system capacity, meaning both the number of customers that can be in the queue and in service is limited. These models are used to capture a wide range of real-world scenarios beyond the assumptions of more restrictive models like M/M/1.
Arrival Probabilities versus Time-Average Probabilities
A key concept in queueing theory is the distinction between the probability an arriving customer encounters all servers busy (an arrival-based probability) and the probability that, at an arbitrary time, all servers are busy (a time-average probability). This difference is particularly important in systems with non-Poisson arrivals because the property known as PASTA (Poisson Arrivals See Time Averages), which equates these probabilities, only holds for Poisson processes. Understanding this distinction is crucial for accurately analyzing customer experience and system performance.
Relationship Between Conditional Queue Length and Waiting Time
The relation E[q | q > 0] = Wq / P[q > 0] links the average number of customers in the queue (given that the queue is not empty) to the average waiting time experienced by those customers, adjusted by the probability that an arriving customer has to wait. This relationship is derived from fundamental principles in queueing theory, such as regeneration arguments and the balance between time-average performance measures and customer-specific experiences. It encapsulates how individual delays aggregate to produce the overall observed congestion in the system.

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Suppose that a customer of the $M / M / 1$ system spends the amount of time $x>0$ waiting in queue before entering service. (a) Show that, conditional on the preceding, the number of other customers that were in the system when the customer arrived is distributed as $1+P$, where $P$ is a Poisson random variable with mean $\lambda$. (b) Let $W_{Q}^{*}$ denote the amount of time that an $M / M / 1$ customer spends in queue. As a by-product of your analysis in part (a), show that $$ P\left[W_{\mathrm{Q}}^{*} \leqslant x\right]=\left\{\begin{array}{ll} 1-\frac{\lambda}{\mu} & \text { if } x=0 \\ 1-\frac{\lambda}{\mu}+\frac{\lambda}{\mu}\left(1-e^{-(\mu-\lambda) x}\right) & \text { if } x>0 \end{array}\right. $$

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