Problem

Prove that $ \frac {d}{dx}$ (cot $ x $) = $ - csc…

02:18

Problem 18 Easy Difficulty

Prove that $ \frac {d}{dx}$ (csc $ x $ ) = sec $ x $ tan $ x. $

Answer

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00:43

Frank L.

Topics

Derivatives

Differentiation

Book Cover for Calculus: Early Tra…

Calculus: Early Transcendentals

Chapter 3

Differentiation Rules

Section 3

Derivatives of Trigonometric Functions

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Video Transcript

It's clear. So in Name right here. So we're trying to prove de over de plex seeker is equal to seek it. Times 10 gin. You know, Stick is one over. Co sign. We're gonna use a quotient Roll. We got zero times. Co sign minus one times negative. Sign over. Co sign. We're gonna done simplify when we get zero minus negative. Sign over. Co signed square, which gives us positive sign on top. So it becomes one over. Co sign. I'm signed over. Co sign, which is equal to seek int times tensions.

Clarissa N.

Topics

Derivatives

Differentiation

Book Cover for Calculus: Early Tra…

Calculus: Early Transcendentals

Chapter 3

Differentiation Rules

Section 3

Derivatives of Trigonometric Functions

Top Calculus 1 / AB Educators

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