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Problem

Prove that $ \frac {d}{dx}$ (cot $ x $) = $ - csc…

02:18

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Problem 18 Easy Difficulty

Prove that $ \frac {d}{dx}$ (csc $ x $ ) = sec $ x $ tan $ x. $


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00:43

Frank Lin

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Calculus 1 / AB

Calculus: Early Transcendentals

Chapter 3

Differentiation Rules

Section 3

Derivatives of Trigonometric Functions

Related Topics

Derivatives

Differentiation

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Top Calculus 1 / AB Educators
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Campbell University

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Lectures

Video Thumbnail

04:40

Derivatives - Intro

In mathematics, a derivative is a measure of how a function changes as its input changes. Loosely speaking, a derivative can be thought of as how much one quantity is changing in response to changes in some other quantity; for example, the derivative of the position of a moving object with respect to time is the object's velocity. The concept of a derivative developed as a way to measure the steepness of a curve; the concept was ultimately generalized and now "derivative" is often used to refer to the relationship between two variables, independent and dependent, and to various related notions, such as the differential.

Video Thumbnail

44:57

Differentiation Rules - Overview

In mathematics, a differentiation rule is a rule for computing the derivative of a function in one variable. Many differentiation rules can be expressed as a product rule.

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01:20

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Problem 16
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Problem 46
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Video Transcript

It's clear. So in Name right here. So we're trying to prove de over de plex seeker is equal to seek it. Times 10 gin. You know, Stick is one over. Co sign. We're gonna use a quotient Roll. We got zero times. Co sign minus one times negative. Sign over. Co sign. We're gonna done simplify when we get zero minus negative. Sign over. Co signed square, which gives us positive sign on top. So it becomes one over. Co sign. I'm signed over. Co sign, which is equal to seek int times tensions.

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Calculus: Early Transcendentals

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Related Topics

Derivatives

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Top Calculus 1 / AB Educators
Anna Marie Vagnozzi

Campbell University

Kayleah Tsai

Harvey Mudd College

Michael Jacobsen

Idaho State University

Joseph Lentino

Boston College

Calculus 1 / AB Courses

Lectures

Video Thumbnail

04:40

Derivatives - Intro

In mathematics, a derivative is a measure of how a function changes as its input changes. Loosely speaking, a derivative can be thought of as how much one quantity is changing in response to changes in some other quantity; for example, the derivative of the position of a moving object with respect to time is the object's velocity. The concept of a derivative developed as a way to measure the steepness of a curve; the concept was ultimately generalized and now "derivative" is often used to refer to the relationship between two variables, independent and dependent, and to various related notions, such as the differential.

Video Thumbnail

44:57

Differentiation Rules - Overview

In mathematics, a differentiation rule is a rule for computing the derivative of a function in one variable. Many differentiation rules can be expressed as a product rule.

Join Course
Recommended Videos

01:20

Prove that $ \frac {d}{dx}$ (csc $ x $ ) = - csc $ x $ cot $ x. $

01:50

Prove that $\frac{\mathrm{d}}{\mathrm{dx}}(\csc x)=-\csc x \cot x$

02:05

Prove that $\frac{\mathrm{d}}{\mathrm{dx}}(\sec \mathrm{x})=\sec x \tan \mathrm…

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Prove that $ \frac {d}{dx}$ (cot $ x $) = $ - csc^2 x. $

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Prove that $\int \csc x d x=\ln |\csc x-\cot x|+C$

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Prove that $\frac{d}{d x}(\csc x)=-\csc x \cot x$

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Prove that $$\frac{d}{d x}(\csc x)=-\csc x \cot x$$

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Prove the identity. $$\tan x \csc x=\sec x$$

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Prove that $$\frac{d}{d x}(\cot x)=-\csc ^{2} x$$
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Evaluate the double integral
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[-/1 Points]
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DEVORESTAT9 4.E.021.
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4. Give the exact value for csc 191 and for tan ~9459

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