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Prove that $ \frac {d}{dx}$ (csc $ x $ ) = sec $ x $ tan $ x. $
00:43
Frank L.
Calculus 1 / AB
Chapter 3
Differentiation Rules
Section 3
Derivatives of Trigonometric Functions
Derivatives
Differentiation
Oregon State University
Harvey Mudd College
Baylor University
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It's clear. So in Name right here. So we're trying to prove de over de plex seeker is equal to seek it. Times 10 gin. You know, Stick is one over. Co sign. We're gonna use a quotient Roll. We got zero times. Co sign minus one times negative. Sign over. Co sign. We're gonna done simplify when we get zero minus negative. Sign over. Co signed square, which gives us positive sign on top. So it becomes one over. Co sign. I'm signed over. Co sign, which is equal to seek int times tensions.
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