Euler's formula states that $e^{jx} = \cos x + j \sin x$. Therefore, we can write $\sin \omega_{0} t$ as the imaginary part of $e^{j\omega_{0} t}$, which gives us:
$$f(t) \sin \omega_{0} t = \frac{1}{2j} \left[f(t)e^{j\omega_{0} t} - f(t)e^{-j\omega_{0}
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