Question
Prove that if $f^{\prime}(x)=g^{\prime}(x)$ for all $x$ in $(a, b),$ then there is a constant $C$ such that $f(x)=g(x)+C$ on $(a, b) .$ [Hint: Apply the Constant Function Theorem to $h(x)=f(x)-g(x) .]$
Step 1
e., $h(x) = f(x) - g(x)$. Show more…
Show all steps
Your feedback will help us improve your experience
Dharmendra Jain and 88 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Prove that if $F^{\prime}(x)=D$ for all $x$ in $(a, b)$ then there is a constant $C$ such that $F(x)=D x+C$ for all $x$ in $(a, b) .$ Hint: Let $G(x)=D x$ and apply Theorem B.
Applications of the Derivative
The Mean Value Theorem for Derivatives
Prove that if $F^{\prime}(x)=0$ for all $x$ in $(a, b)$ then there is a constant $C$ such that $F(x)=C$ for all $x$ in $(a, b) .$ Hint: Let $G(x)=0$ and apply Theorem B.
Suppose that $f^{\prime}(x)=f(x)$ for all $x .$ Prove that $f(x)=$ $\left.\mathrm{Ce}^{x} \text { for some constant } C . \text { [Hint: Consider } f(x) / e^{x} .\right]$
Short-Cuts to Differentiation
Theorems About Differentiable Functions
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD