00:01
In this question, it is given that f and g are two continuous functions on the close interval a to b.
00:08
It is given if f of x is always greater than equal to g of x on the interval a to b.
00:15
We need to prove that the integral of the function f of x for the limit a to b will also be greater than equal to the integral of function g of x for the limit a to b.
00:25
Now, from the definition of definite integrals, we have, that is the definite integral of f of x, that is integral f of x, dot dx for the limit a to b is equal to, is actually equal to, that is the sum of, that is limit of sum, limit, n tends to infinite, a limit on the, that is, that is, f of u .i times delta x and i is from 1 to n now we know that f of x is greater than equal to 0 and delta x will also be greater than 0 now from these two values we will get that f of ui times delta x will also be greater than 0 that is therefore summation of f of ui times delta x will also be greater than 0 for equal to 1 to n now from here by the properties of the limits we will have that is limit n tends to infinite on the that is summation of f of ui times delta x for the limit that is for i equal to 1 to n will be greater than or equal to limit on that is limit of n tends to infinite on zero which is also equal to zero therefore from here we can conclude that this limit of sum which is that is limit and tends to infinite summation of f of ui times delta x for i equal to 1 to n will be greater than equal to 0 now we can see on the left -hand side this expression is just equal to the, that is definite integral of function f of x for the limit a to b.
02:41
Therefore, we will get from here that that is the integral of f of x for the limit a to b.
02:50
Dx will also be greater than equal to 0.
02:53
So from here, we got that if the function is greater than equal to 0, then its integral will also be greater than equal to 0...