Question
Prove that if $\mathbf{v}_1, \mathbf{v}_2$ form a basis of an inner product space $V$ and $\left\|\mathbf{v}_1\right\|=\left\|\mathbf{v}_2\right\|$, then $\mathbf{v}_1+\mathbf{v}_2$ and $\mathbf{v}_1-\mathbf{v}_2$ form an orthogonal basis of $V$.
Step 1
We know that $\mathbf{v}_1$ and $\mathbf{v}_2$ form a basis for the inner product space $V$. This implies that $\mathbf{v}_1$ and $\mathbf{v}_2$ are linearly independent and span $V$. Additionally, we are given that $\left\|\mathbf{v}_1\right\| = Show more…
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Key Concepts
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Let $V$ be a real inner product space. (a) Prove that for all $\mathbf{v}, \mathbf{w} \in V$ $\|\mathbf{v}+\mathbf{w}\|^{2}=\|\mathbf{v}\|^{2}+2\langle\mathbf{v}, \mathbf{w}\rangle+\|\mathbf{w}\|^{2}$ [Hint: $\left.\|\mathbf{v}+\mathbf{w}\|^{2}=\langle\mathbf{v}+\mathbf{w}, \mathbf{v}+\mathbf{w}\rangle .\right]$ (b) Two vectors $\mathbf{v}$ and $\mathbf{w}$ in an inner product space $V$ are called orthogonal if $\langle\mathbf{v}, \mathbf{w}\rangle=0 .$ Use (a) to prove the general Pythagorean Theorem: If $\mathbf{v}$ and $\mathbf{w}$ are orthogonal in an inner product space $V,$ then $$\|\mathbf{v}+\mathbf{w}\|^{2}=\|\mathbf{v}\|^{2}+\|\mathbf{w}\|^{2}$$
Definition of an Inner Product Space
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