Question
Prove that:If $\sin ^{-1} x+\sin ^{-1} y+\sin ^{-1} z=\frac{3 \pi}{2}$, then prove that$x y+y z+z x=3$
Step 1
Step 1: We know that $\sin ^{-1} x+\sin ^{-1} y+\sin ^{-1} z=\frac{3 \pi}{2}$, which implies that $x=\sin(\frac{3 \pi}{2}-\sin ^{-1} y-\sin ^{-1} z)$. Show more…
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