00:01
Okay, so for this exercise we're going to suppose that a is going to be a triangular matrix.
00:06
We need to show the following.
00:08
So first we need to show that a is an invertible matrix if and only if each element in diagonal is different from zero.
00:16
And the second thing that we need to show is that the diagonal elements of the inverse matrix if exist, of course, are going to be the reciprocals of the diagonal elements in the matrix a.
00:28
Okay, so let's start with the first one.
00:33
It is not that hard to prove it because basically we know that a matrix a is invertible if and only if the determinant of the matrix is different from zero.
00:51
And we know that the determinant of a triangular matrix, in this case a, corresponds to the multiplication of the diagonal element.
01:02
A1 times a22 times a33 up to a and n.
01:12
So here we have that the determinant of a because it's a triangular matrix is going to be equals to the multiplication of the diagonal elements.
01:21
And here is clear that this is different from zero if each aith -ith is different from zero.
01:33
And with that we end the proof of this first part.
01:39
Okay, as i mentioned, is not that hard.
01:43
The second one, we need to consider that let's suppose that indeed, a is invertible, then we know that the inverse matrix is going to be equals to the adjoin matrix of a divided the determinant of a...