Question
Prove that:Let $m=\frac{\left(\tan ^{-1} 1+\tan ^{-1} 2+\tan ^{-1} 3\right)}{\left(\cot ^{-1} 1+\cot ^{-1} 2+\cot ^{-1} 3\right)}$, then prove that$(m+2)^{m+1}=64$
Step 1
Step 1: We are given that $m=\frac{\left(\tan ^{-1} 1+\tan ^{-1} 2+\tan ^{-1} 3\right)}{\left(\cot ^{-1} 1+\cot ^{-1} 2+\cot ^{-1} 3\right)}$. Show more…
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