00:01
Hello, so you want to show that if a, b, and c are mutually independent, then a intersect b, and c are independent, and a, union, b, and c are going to be independent.
00:12
So here we have that a, b, and c are mutually independent, then we have that p of a intersect b, intersect c is going to be equal to p of a times p of b times p of c.
00:40
And now we have then that probability of a intersect b given c is going to be equal to probability of a intersect b intersect c all over probability of c.
01:09
So probability of a intersect b intersect c all divided by p of c, which is then going to be equal to probability of a times probability of b, then probably a to c all over c, which is equal to p of a times p of b, which is equal to probability of a intersect b...
