00:02
We want to show that the complex number c does not satisfy the order properties.
00:08
That is, it is impossible to find a subset c plus of the complex numbers that satisfies properties similar to those stated for the real numbers.
00:24
So let's say we have here the properties of the real numbers regarding the order.
00:33
The set of real numbers contains a subset r plus satisfying the following properties.
00:42
First property, given any a in the real numbers, exactly one and only one of the following statements is true.
00:55
A is in r plus, a is zero, or negative a is in r plus.
01:03
The second property, if two numbers a and b are in r plus, then the sum of the numbers is also in r plus as well as the product of the numbers.
01:21
So we're going to prove that does not exceed a set, a subset of c plus of the nile complex number, satisfying these two properties.
01:30
For that, let's suppose that such a set exist.
01:34
So let's suppose that such a set c plus exists.
01:51
I'm not going to write again the properties.
01:54
We are clear that if we take any complex number, that is the translation of these two properties to the complex numbers, is putting here complex number and here c plus.
02:09
That is the subset c plus of c which we state that exists.
02:18
So going that, let's prove that is impossible.
02:23
That is supposing that this set c plus exists, we're going to get some contradiction.
02:33
Okay, so if that set exists, we know that if we take i, the complex number i, that is zero, in its real part and one it's in its imaginary part.
02:49
Then we get to have applying property 1 by property 1, i belongs to c plus or i is 0 or i or negative i belongs to c plus.
03:14
Remember that here when we talk about negative i, the sum, the product, we are talking about the product, the sum in the company.
03:23
Number...