Question
Prove that $P(E \cup F \cup G)=P(E)+P(F)+P(G)-P\left(E^{c} F G\right)-P\left(E F^{c} G\right)-$ $P\left(E F G^{c}\right)-2 P(E F G) .$
Step 1
If E and F are mutually exclusive events, then by axiom 3 of probability we have: \[P(E \cup F) = P(E) + P(F - E)\] This is our first equation. Show more…
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