Question
Prove that $Q(\sqrt{2}, \sqrt[3]{2}, \sqrt[4]{2}, \ldots)$ is an algebraic extension of $Q$ but not a finite extension of $Q$. (This exercise is referred to in this chapter.)
Step 1
This field is generated over \( \mathbb{Q} \) by adjoining the elements \( \sqrt{2}, \sqrt[3]{2}, \sqrt[4]{2}, \ldots \). Show more…
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