Question
Prove that the following formula holds for the $k$ th-order differences of a sequence $h_{0}, h_{1}, \ldots, h_{n}, \ldots:$$$\Delta^{k} h_{n}=\sum_{j=0}^{k}(-1)^{k-j}\left(\begin{array}{l}k \\j\end{array}\right) h_{n+j}$$
Step 1
We have: $$\Delta^1 h_n = h_{n+1} - h_n$$ Now, let's plug in the formula for the first-order differences: $$\Delta^1 h_n = \sum_{j=0}^{1}(-1)^{1-j}\left(\begin{array}{l}1 \\j\end{array}\right) h_{n+j}$$ Expanding the sum, we get: $$\Delta^1 h_n = Show more…
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