Question
Prove that the function $\psi=A e^{\alpha x}+B e^{-\alpha x}$ satisfies the equation $\psi^{\prime \prime}=\alpha^{2} \psi$ for any two constants $A$ and $B$.
Step 1
The first derivative of $\psi$ with respect to $x$ is given by: \[\psi' = A\alpha e^{\alpha x} - B\alpha e^{-\alpha x}\] Show more…
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