Question
Prove that the Laplacian operator $\Delta[f]=\frac{\partial^2 f}{\partial x^2}+\frac{\partial^2 f}{\partial y^2}$ defines a linear function on the vector space of twice continuously differentiable functions $f(x, y)$.
Step 1
To prove that the Laplacian operator $\Delta$ is linear, we need to show that it satisfies two properties for any functions $f, g$ in the space of twice continuously differentiable functions and any scalar $c$: Show more…
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Key Concepts
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Show that $$\nabla \cdot \nabla f=\frac{\partial^{2} f}{\partial x^{2}}+\frac{\partial^{2} f}{\partial y^{2}}+\frac{\partial^{2} f}{\partial z^{2}}$$ This is known as the Laplacian and is also written $\nabla^{2} f$.
Vector Calculus
Curl and Divergence
Prove the identity, assuming that $\mathbf{F}, \sigma$, and $G$ satisfy the hypotheses of the Divergence Theorem and that all necessary differentiability requirements for the functions $f(x, y, z)$ and $g(x, y, z)$ are met.$$ \begin{aligned} &\iint \nabla f \cdot \mathbf{n} d S=\iiint_{\sigma} \nabla^{2} f d V \\ &\left(\nabla^{2} f=\frac{\partial^{2} f}{\partial x^{2}}+\frac{\partial^{2} f}{\partial y^{2}}+\frac{\partial^{2} f}{\partial z^{2}}\right) \end{aligned} $$
Topics In Vector Calculus
The Divergence Theorem
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