Question
Prove that the number of permutations of at most $m A^{\prime} s$ and at most $n B^{\prime} s$ equals$$\left(\begin{array}{c}m+n+2 \\m+1\end{array}\right)-1$$.
Step 1
This means that we can have 0 to $m$ occurrences of $A'$ and 0 to $n$ occurrences of $B'$ in the permutation. Show more…
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