10) and (8.12) from the context of the Lane-Emden equation:
(8.10) $\frac{1}{\xi^2}\frac{d}{d\xi}\left(\xi^2\frac{d\theta}{d\xi}\right) = -\theta^n$
(8.12) $\frac{d\ln\rho}{d\ln r} = -\frac{1}{\xi^2}\frac{d\theta}{d\xi}$
Now, let's consider the relationship
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