00:01
All right, so here for the quasi -static antibiotic process, we have that q equals zero.
00:08
So by the first law, we have that delta u is equal to q minus w, which is negative w.
00:17
And then for the ideal gas, we have that delta u is equal to cv -tf minus t -i.
00:27
So we have that cv times tf minus ti equals negative w.
00:35
So w is equal to cv times t initial minus t final.
00:42
So the images part a should likely be here that w is equal to cv, ti minus tf, not negative cv, ti, minus tf, depending on the sign convention.
01:02
And then also, since we have that pv is equal to n -r -t, we get that cv -ti -minus t -f is equal to c -v -v -over n -r times p -i -v -f, using gamma minus 1 is equal to r over c -v -v -v, p -i -v -i -minus p -f -v -f divided by gamma minus 1...