💬 👋 We’re always here. Join our Discord to connect with other students 24/7, any time, night or day.Join Here!
Get the answer to your homework problem.
Try Numerade free for 30 days
Like
Report
Prove the following:$$\cot 4 x(\sin 5 x+\sin 3 x)=\cot x(\sin 5 x-\sin 3 x)$$
Precalculus
Chapter 3
Trigonometric Functions
Section 3
Trigonometry
Johns Hopkins University
Piedmont College
Harvey Mudd College
Lectures
07:16
In mathematics, a continuo…
04:09
00:58
Prove the identity.$$\…
05:01
Prove the identity$$
02:48
Prove that each equation i…
01:10
Proving an Identity Prove …
02:38
Verify each identity.$…
00:30
01:37
01:29
Proving ldentities Prove t…
02:24
02:52
in discussion we have to prove that cold four X times sign five X plus sign three X. Equal to cortex times signed five X. Negative sign three X. So now here we have to big allergies and we simplify this. So here A. Which is equal to cool four X times sign five X plus sign three X. No here we know that cortex equal to co sex upon Synnex. And we have a formula four ST E plus sign B. Equal to two times sign A plus B upon to times goes A negative B up on two. So and here you can see that equal to five X. And be equal to three X. Now we apply that formula here so we get good for acts value is sign four X. Sorry calls for eggs upon saying four X times two times saying five X plus three eggs up on two times goes five X. Negative three X upon to. Now we simplify this. So here we get of course four eggs upon signed for eggs times two times sign for X. Times Ghost X. So we get two times course four eggs times cause X. No we take oranges and we simplify this. So here arch is equal to cortex times sane five X. Negative sign three X. So we have a formula for sane E. Negative sign B. Equal to two times sine E negative B upon to times cause april is be upon to and here equal to five eggs be equal to cree acts. So now we apply the formula here so we get cortex values co sex upon Synnex times two times saying five X. Negative three X upon to times course five X plus three X. Upon to. So now we simplify this. So here we get go sex upon cynic times two times saying X. Times of course four eggs. Now we simplify this. So here we get two times, of course four X times goes eggs. So here you can see that the value of alleges equal to the value of oranges, so hence proof and it is final.
View More Answers From This Book
Find Another Textbook
Numerade Educator
In mathematics, a continuous function is a function for which sufficiently s…
Prove the identity.$$\frac{\sin (6 x)+\sin (4 x)}{\sin (6 x)-\sin (4 x)}…
Prove the identity$$\frac{\sin x+\sin 2 x+\sin 3 x+\sin 4 x+\sin 5 x…
Prove that each equation is an identity.$$\frac{\sin 3 x+\sin 5 x}{\sin …
Proving an Identity Prove the identity$$\frac{\sin x+\sin 2 x+\sin 3 x+\…
Verify each identity.$\tan 4 x=\frac{\sin 5 x+\sin 3 x}{\cos 3 x+\cos 5 …
Prove the identity.$$\cot x \sin x=\cos x$$
Prove the identity.$$\frac{\sin x-\sin 3 x}{\cos x-\cos 3 x}=-\cot 2 x$$…
Proving ldentities Prove the identity.$$\frac{\sin x+\sin 5 x}{\cos …
Prove the identity.$$\frac{\sin 4 x+\sin 6 x}{\cos 4 x-\cos 6 x}=\cot x$…
Verify each identity.$-\tan 4 x=\frac{\cos 3 x-\cos 5 x}{\sin 3 x-\sin 5…
02:59
Choose the correct answer.$\int \frac{d x}{\sqrt{9 x-4 x^{2}}}$ equals
02:18
If the areas of two similar triangles are equal, prove that they are congrue…
07:44
For each of the differential equations in Exercises 1 to 10 , find the gener…
05:52
Prove the following by using the principle of mathematical induction for all…
Check whether $-150$ is a term of the AP: $11,8,5,2 \ldots$
10:47
07:08
Find the coordinates of the points of trisection of the line segment joining…
03:23
$\mathrm{ABCD}$ is a trapezium in which $\mathrm{AB}$ II $\mathrm{DC}$ and i…
03:43
How many elements has $\mathrm{P}(\mathrm{A})$, if $\mathrm{A}=\phi ?$
03:05
Find two positive numbers $x$ and $y$ such that their sum is 35 and the prod…
Create an account to get free access
Join Numerade as a
By clicking Sign up you accept Numerade's Terms of Service and Privacy Policy
or sign up with
Already have an account? Log in