Prove the following for all $x \in \mathbb{R}$ :
(i) $\sin 2 x=2 \sin x \cos x$,
(ii) $\cos 2 x=\cos ^{2} x-\sin ^{2} x=2 \cos ^{2} x-1=1-2 \sin ^{2} x$,
(iii) $\sin 3 x=3 \sin x-4 \sin ^{3} x$
(iv) $\cos 3 x=4 \cos ^{3} x-3 \cos x$.
Deduce that
$\sin \frac{\pi}{4}=\frac{1}{\sqrt{2}}=\cos \frac{\pi}{4}, \quad \sin \frac{\pi}{3}=\frac{\sqrt{3}}{2}=\cos \frac{\pi}{6}, \quad \cos \frac{\pi}{3}=\frac{1}{2}=\sin \frac{\pi}{6}$