Question
Prove the following for all $x \in \mathbb{R}$. $\sin (\pi-x)=\sin x, \quad \sin ((\pi / 2)-x)=\cos x, \quad \sin ((\pi / 2)+x)=\cos x$,$\cos (\pi-x)=-\cos x, \quad \cos ((\pi / 2)-x)=\sin x, \quad \cos ((\pi / 2)+x)=-\sin x .$
Step 1
Using the sine function's property of symmetry, we can use the unit circle. The angle \(\pi - x\) corresponds to a point in the second quadrant where the sine value is the same as that of \(x\) in the first quadrant. Thus, we have: \[ \sin(\pi - x) = \sin Show more…
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