Question

Prove the following orthogonality relations for the Stirling numbers of the first and second kind. For all $n, j \in \mathbb{N}$, with $0 \leq j \leq n$, (a) $\sum_{k=j}^n s(n, k) S(k, j)=\delta_{n, j}$, and (b) $\sum_{k=j}^n S(n, k) s(k, j)=\delta_{n, j}$.

   Prove the following orthogonality relations for the Stirling numbers of the first and second kind. For all $n, j \in \mathbb{N}$, with $0 \leq j \leq n$,
(a) $\sum_{k=j}^n s(n, k) S(k, j)=\delta_{n, j}$, and
(b) $\sum_{k=j}^n S(n, k) s(k, j)=\delta_{n, j}$.
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A First Course in Enumerative Combinatorics
A First Course in Enumerative Combinatorics
Carl G. Wagner 1st Edition
Chapter 6, Problem 13 ↓

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Step 1

The Stirling numbers of the first kind, denoted \( s(n, k) \), count the number of permutations of \( n \) elements with exactly \( k \) permutation cycles. The Stirling numbers of the second kind, denoted \( S(n, k) \), count the number of ways to partition \( n  Show more…

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Prove the following orthogonality relations for the Stirling numbers of the first and second kind. For all $n, j \in \mathbb{N}$, with $0 \leq j \leq n$, (a) $\sum_{k=j}^n s(n, k) S(k, j)=\delta_{n, j}$, and (b) $\sum_{k=j}^n S(n, k) s(k, j)=\delta_{n, j}$.
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