00:01
Good day.
00:03
Today we're going to be looking at problem number 36.
00:07
And again, i didn't really bother writing out the whole problem, but basically the summary is, you know, we have a, we have a non -homogeneous system here.
00:25
We have a non -homogeneous system, and we have a homogeneous system.
00:30
And we're assuming we have a, we have a, we have a, we have a, we have a, fundamental solution set here and that xp is a particular solution and what we want to do is show any solution can be written any solution can be written of this form okay so um okay and now the trick here okay so this is what this is our goal now what do we want to do okay so so basically what we do is we assume we have any two solutions to 36.
01:08
Okay.
01:09
So we have any two solutions to the non -homogeneous ode.
01:18
And this implies, of course, i'm just rewriting both of this.
01:24
That z1 of t and z2, well, the derivatives are equal to, of course, here.
01:34
And now this implies what? well, what implies is if i subtract the two of these expressions, so if i take the difference of these two expressions, what do i get? well, when i take the difference, the f of t is going to cancel.
01:57
So i'm going to get this.
02:00
I'm going to get, well, yeah, i'm going to get this here.
02:04
And that leads me to this expression here.
02:09
Now, a is a matrix, and z2 of t and z1 of t are vectors.
02:19
So because of this, i can get this expression here.
02:24
This is just, again, in case you guys have forgotten.
02:31
I hope you haven't.
02:32
But what this is just a x plus a y is just a x plus y is just a x plus y okay so that's all i'm doing it just looks kind of vamp up because it's got the twos and the t's and everything in here that's really all i'm doing um okay so now of course z2 of t minus z one of t is a vector and so what does that mean? well, of course, if we look at the difference here, i just define zt to be the difference...