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Prove the given statement about subsets $A$ and $B$ of $\mathbb{R}^{n} .$ A proof for an exercise may use results of earlier exercises.If $A \subset B,$ then $\operatorname{conv} A \subset \operatorname{conv} B$

Suppose that $A \subset B$ . We allready know that $B$ \subsetcomv(B), so $A \subset B$ Conv $( B )$ .Also, by definition, corrv $( B )$ is compex set, so result follows from exercise 17.

Calculus 3

Chapter 8

The Geometry of Vector Spaces

Section 3

Convex Combinations

Vectors

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No, let's Suppose is a subset off B or A s Continue to be as we're giving. No, we already know. We know that be is always a subset or he's always contained in the convents all of being. So this implies that it is the substance of being on B is contained in the convicts all of being no, by definition, convicts All off being is a convict sets. Therefore we can use exercise. Seventh scene. This would imply dots the convicts because you are birds. It is a subset of the convicts. 11 just invited this way so as to be clear, so is the source of these. This is a convict sets. So that implies that the convicts all off the is this so sets off contacts or

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