Question
Prove the identities.$$\frac{\cos (A+B)}{\cos (A-B)}=\frac{1-\tan A \tan B}{1+\tan A \tan B}$$
Step 1
These formulas are given by: $$\cos(A+B) = \cos A \cos B - \sin A \sin B$$ $$\cos(A-B) = \cos A \cos B + \sin A \sin B$$ Show more…
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